Could not determine type for: java.util.List, at table: user, for columns: [org.hibernate.mapping.Column(login_record_list)]

言曌 2018年03月26日10:01:13 7 6316 views

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在使用 Spring Data JPA 的时候，使用 @OneToMany @ManyToMany 报错如下

Caused by: org.hibernate.MappingException: Could not determine type for: java.util.List, at table: user, for columns: [org.hibernate.mapping.Column(login_record_list)]

 at org.hibernate.mapping.SimpleValue.getType(SimpleValue.java:455)

 at org.hibernate.mapping.SimpleValue.isValid(SimpleValue.java:422)

 at org.hibernate.mapping.Property.isValid(Property.java:226)

 at org.hibernate.mapping.PersistentClass.validate(PersistentClass.java:597)

 at org.hibernate.mapping.RootClass.validate(RootClass.java:265)

 at org.hibernate.boot.internal.MetadataImpl.validate(MetadataImpl.java:329)

 at org.hibernate.boot.internal.SessionFactoryBuilderImpl.build(SessionFactoryBuilderImpl.java:459)

 at org.hibernate.jpa.boot.internal.EntityManagerFactoryBuilderImpl.build(EntityManagerFactoryBuilderImpl.java:892)

 ... 23 common frames omitted

解决方案：

注解要么全部放在字段上，要么全部放在 get 方法上，不能混合使用！

因为我这个类其他的注解都是在标在字段上

所以，这种是正确的

@ManyToMany(cascade = CascadeType.ALL)
@JoinTable(name = "user_authority",
joinColumns = {@JoinColumn(name = "user_id", referencedColumnName = "id")},
inverseJoinColumns = {@JoinColumn(name = "authority_id", referencedColumnName = "id")}
)
private List<Authority> authorities;