js实现动态几何图案背景

言曌 2017年01月28日22:05:58 2 5083 views

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效果图：

直接贴代码了

<script type="text/javascript">
! function () {
function o(w, v, i) {
return w.getAttribute(v) || i
}
function j(i) {
return document.getElementsByTagName(i)
}
function l() {
var i = j("script"),
w = i.length,
v = i[w - 1];
return {
l: w,
z: o(v, "zIndex", -1),
o: o(v, "opacity", 0.5),
c: o(v, "color", "0,0,0"),
n: o(v, "count", 99)
}
}
function k() {
r = u.width = window.innerWidth || document.documentElement.clientWidth || document.body.clientWidth, n = u.height = window.innerHeight || document.documentElement.clientHeight || document.body.clientHeight
}
function b() {
e.clearRect(0, 0, r, n);
var w = [f].concat(t);
var x, v, A, B, z, y;
t.forEach(function (i) {
i.x += i.xa, i.y += i.ya, i.xa *= i.x > r || i.x < 0 ? -1 : 1, i.ya *= i.y > n || i.y < 0 ? -1 : 1, e.fillRect(i.x - 0.5, i.y - 0.5, 1, 1);
for (v = 0; v < w.length; v++) {
x = w[v];
if (i !== x && null !== x.x && null !== x.y) {
B = i.x - x.x, z = i.y - x.y, y = B * B + z * z;
y < x.max && (x === f && y >= x.max / 2 && (i.x -= 0.03 * B, i.y -= 0.03 * z), A = (x.max - y) / x.max, e.beginPath(), e.lineWidth = A / 2, e.strokeStyle = "rgba(" + s.c + "," + (A + 0.2) + ")", e.moveTo(i.x, i.y), e.lineTo(x.x, x.y), e.stroke())
}
}
w.splice(w.indexOf(i), 1)
}), m(b)
}
var u = document.createElement("canvas"),
s = l(),
c = "c_n" + s.l,
e = u.getContext("2d"),
r, n, m = window.requestAnimationFrame || window.webkitRequestAnimationFrame || window.mozRequestAnimationFrame || window.oRequestAnimationFrame || window.msRequestAnimationFrame || function (i) {
window.setTimeout(i, 1000 / 45)
},
a = Math.random,
f = {
x: null,
y: null,
max: 20000
};
u.id = c;
u.style.cssText = "position:fixed;top:0;left:0;z-index:" + s.z + ";opacity:" + s.o;
j("body")[0].appendChild(u);
k(), window.onresize = k;
window.onmousemove = function (i) {
i = i || window.event, f.x = i.clientX, f.y = i.clientY
}, window.onmouseout = function () {
f.x = null, f.y = null
};
for (var t = [], p = 0; s.n > p; p++) {
var h = a() * r,
g = a() * n,
q = 2 * a() - 1,
d = 2 * a() - 1;
t.push({
x: h,
y: g,
xa: q,
ya: d,
max: 6000
})
}
setTimeout(function () {
b()
}, 100)
}();
</script>