8. String to Integer (atoi) 【Medium】

avatar 2020年08月30日22:09:08 6 2126 views
博主分享免费Java教学视频,B站账号:Java刘哥

Question

Implement atoi which converts a string to an integer.

The function first discards as many whitespace characters as necessary until the first non-whitespace character is found. Then, starting from this character, takes an optional initial plus or minus sign followed by as many numerical digits as possible, and interprets them as a numerical value.

The string can contain additional characters after those that form the integral number, which are ignored and have no effect on the behavior of this function.

If the first sequence of non-whitespace characters in str is not a valid integral number, or if no such sequence exists because either str is empty or it contains only whitespace characters, no conversion is performed.

If no valid conversion could be performed, a zero value is returned.

Note:

  • Only the space character ' ' is considered as whitespace character.
  • Assume we are dealing with an environment which could only store integers within the 32-bit signed integer range: [−231,  231 − 1]. If the numerical value is out of the range of representable values, INT_MAX (231 − 1) or INT_MIN (−231) is returned.

Example 1:

Input: "42"
Output: 42

Example 2:

Input: "   -42"
Output: -42
Explanation: The first non-whitespace character is '-', which is the minus sign.
             Then take as many numerical digits as possible, which gets 42.

Example 3:

Input: "4193 with words"
Output: 4193
Explanation: Conversion stops at digit '3' as the next character is not a numerical digit.

Example 4:

Input: "words and 987"
Output: 0
Explanation: The first non-whitespace character is 'w', which is not a numerical 
             digit or a +/- sign. Therefore no valid conversion could be performed.

Example 5:

Input: "-91283472332"
Output: -2147483648
Explanation: The number "-91283472332" is out of the range of a 32-bit signed integer.
             Thefore INT_MIN (−231) is returned.

 

My Answer

class Solution {
   public int myAtoi(String str) {
        int index = 0, sign = 1, total = 0;
        // 空字符串
        if (str.length() == 0) {
            return 0;
        }

        // 处理空格问题,直接右移
        while (index < str.length() && str.charAt(index) == ' ') {
            index++;
        }
        // 判断是否有+/-
        if (index < str.length() && (str.charAt(index) == '+' || str.charAt(index) == '-')) {
            sign = str.charAt(index) == '+' ? 1 : -1;
            index++;
        }

        // 处理字符串
        while (index < str.length()) {
            int digit = str.charAt(index) - '0';

            // 如果遇到非数字字符,直接返回
            if (digit < 0 || digit > 9) {
                break;
            }

            // 如果数字大于最大值,返回最大值/最小值
            if (Integer.MAX_VALUE / 10 < total ||
                    Integer.MAX_VALUE / 10 == total && Integer.MAX_VALUE % 10 < digit) {
                return sign == 1 ? Integer.MAX_VALUE : Integer.MIN_VALUE;
            }

            total = 10 * total + digit;
            index++;
        }
        return total * sign;
    }
}

 

  • 微信
  • 交流学习,有偿服务
  • weinxin
  • 博客/Java交流群
  • 资源分享,问题解决,技术交流。群号:590480292
  • weinxin
avatar

发表评论

avatar 登录者:匿名
匿名评论,评论回复后会有邮件通知

  

已通过评论:0   待审核评论数:0